An approximation to
is given by the so‐called Stirling's formula.
Theorem 3.4.3 (Stirling's Formula) We have
(3.29) 
where the sign
means that the ratio of the two sides tends to 1 as
.
We shall not give the proof here, but interested readers can find it in more advanced texts, for example, in Chow and Teicher (1997).
A group of
boys and
girls is divided at random into two equal parts. What is the probability
and its approximation for large
, that boys and girls are divided evenly between the two groups?
Clearly, the number of ways a group can be divided into two equal parts is
. The number of ways
boys can be divided evenly is
and the same holds for girls. Thus,
(3.30) 
which, based on ( 3.29), can be approximated by
For example, in the case of 16 boys and 16 girls
, the approximate chances of dividing both sexes evenly are about
The exact value is 0.2756.
1 3.4.1 Show that if then(i) Use the definition of binomial coefficients as ratios of the factorials. (ii) Use directly the interpretation of the binomial coefficients as the number of subsets of a given size. (iii) How many ways can one choose an ‐element subset from a ‐element subset from a ‐element subset from a ‐element subset from a element set? (where ).
2 3.4.2 Find the coefficient of the term in the expansion of .
3 3.4.3 Use the argument analogous to that in Theorem 3.3.2to show that if , and , then
4 3.4.4 Use Stirling's formula to approximate the number of ways: (i) A set of size can be partitioned into two equal parts. (ii) A set of size can be partitioned into three equal parts.
5 3.4.5 Approximate the probability that every state will be represented in the committee in Problem 3.3.1(i).
1 1The integer part of , [], is the largest integer not exceeding ( etc.).
2 2This property, called exchangeability of events, will be discussed in more detail in Section 4.6.
3 3The discarded cards are not mixed with the deck. Assume that the player receives the replacement of the discarded cards from the unused remainder of the deck.
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