Robert Bartoszynski - Probability and Statistical Inference

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Updated classic statistics text, with new problems and examples
Probability and Statistical Inference, Third Edition
Probability and Statistical Inference 

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Example 313 Poker We now consider the probabilities of several poker hands - фото 1308

Example 3.13 Poker

We now consider the probabilities of several poker hands (some students will probably say that finally the book gives some useful information).

In poker, five cards are dealt to a player from a standard deck of 52 cards. The number of possible hands is therefore Probability and Statistical Inference - изображение 1309. The lowest type of hand is that containing one pair (two cards of the same denomination, plus three unmatched cards). To find the number of possible hands containing one pair, one can think in terms of consecutive choices leading to such a hand:

1 The denomination of the cards in a pair can be chosen in ways.

2 The suits of the pair can be chosen in ways.

3 The choice of denominations of the remaining three cards can be made in ways.

4 The suits of those three cards may be chosen in ways. Altogether, combining (a)–(d), we have

The next kind of hand is the one containing two pairs. Here the argument is as follows:

1 The denominations of the two pairs can be selected in ways.

2 The suits of cards in these two pairs can be selected in ways.

3 The remaining card may be chosen in ways (two denominations are eliminated).

Combining (a)–(c), we have

Finally we calculate the probability of a straight probabilities of remaining - фото 1310

Finally, we calculate the probability of a straight (probabilities of remaining hands are left as exercise). A straight is defined as a hand containing five cards in consecutive denominations but not of the same suit (e.g., 9, 10, jack, queen, and king). An ace can appear at either end, so we could have a straight of the form ace, 2, 3, 4, 5, as well as 10, jack, queen, king, ace.

The number of hands with a straight can be computed as follows: Each such hand is uniquely determined by the lowest denomination (ace, Probability and Statistical Inference - изображение 1311) in 10 ways. Then, the suits of five cards are chosen in картинка 1312ways: is the total number of choices of suits and we subtract 4 selections in which - фото 1313is the total number of choices of suits, and we subtract 4 selections in which all cards are of the same suit. Thus,

Problems 1 331 i A committee of size 50 is to be formed out of the US - фото 1314

Problems

1 3.3.1 (i) A committee of size 50 is to be formed out of the US Senate at random. Find the probability that each state will be represented. (ii) If a committee of size is to be formed out of the US Senate find how large must be in order for the event “at least one senator from Ohio is included” to be more likely than the event “no senator from Ohio is included.”

2 3.3.2 A shipment of 30 items is received. For the quality control, three items are randomly selected, and if more than one of them is defective then the whole shipment is rejected. Find the probability that the shipment will be accepted if it has: (i) Three defective items (ii) Ten defective items.

3 3.3.3 How many ways can one order the deck of 52 cards so that all four kings are next to each other?

4 3.3.4 Peter lives at the corner of 2nd Avenue and 72nd Street. His office is in the building at a corner of 7th Avenue and 78th Street. The streets and avenues in the city form a perpendicular grid, with no streets or passages in the middle of the blocks. Peter walks to work along either street or avenue, always in the direction that gets him closer to his office. He always returns home by subway, so he walks across town only once a day. (i) How many different paths can Peter choose to go to work? (ii) If Peter makes a list of all possible paths and chooses one of them randomly every morning, how likely it is that he will not walk 4th Avenue between 75th and 76th streets during the next five working days?

5 3.3.5 (Poker Hands) (Poker Hands) Find the probability of each of the following hands: (i) Royal flush (ace, king, queen, jack, and 10 in one suit), (ii) Straight flush (five cards of one suit in a sequence, but not a royal flush), (iii) Flush (five cards in one suit, but not a straight flush nor a royal flush), (iv) Four‐of‐a‐kind (four cards of the same denomination), (v) Full house (one pair and one triple of the same denomination), (vi) Three‐of‐a‐kind (three cards of the same denomination plus two cards unmatched).

6 3.3.6 Find the probability that a poker hand will contain two pairs (one red and the other black) and one unmatched card.

7 3.3.7 A poker player has Q. He discards and Q and obtains 2 cards. 3(i) What is the probability that he will have a straight? (ii) Answer the same question if Q is replaced by J (i.e., he discards and J).

8 3.3.8 A poker player has Q. She discards and Q and obtains 2 cards. What is the probability that she will have: (i) A straight flush. (ii) A flush, but not a straight flush. (iii) A straight, but not a straight flush.

9 3.3.9 A poker player has three‐of‐a‐kind. He discards the two unmatched cards and obtains two new cards. Find the probability that he will have: (i) Three‐of‐a‐kind. (ii) Four‐of‐a‐kind. (iii) A full house.

10 3.3.10 (i) If balls are put at random into boxes, find the probability of exactly one box remaining empty? (ii) If balls are randomly placed into boxes (), labeled , find the probability that no box is empty.

11 3.3.11 Compute probabilities of winning numbers in lotteries, where the player chooses: (i) 5 out of 44 numbers. (ii) 6 out of 55 numbers.

12 3.3.12 Find the number of polygonal lines with vertices , where is as in Example 3.12and with possible edges leading from to or , connecting the points: (i) and . (ii) and . iii) and .

13 3.3.13 Find the number of polygonal lines (as in Problem 3.3.12) that join the points (2,3) and (16, 5) and: (i) Never touch the ‐axis. (ii) Never touch the line = 7.

3.4 Multinomial Coefficients

Choosing a subset of size картинка 1315out of a set of size картинка 1316is logically equivalent to partitioning the set of size картинка 1317into two subsets, one of size and the other of size The number of such partitions is by definition - фото 1318and the other of size The number of such partitions is by definition The theorem below - фото 1319. The number of such partitions is, by definition,

Probability and Statistical Inference - изображение 1320

The theorem below generalizes this scheme.

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