Mary Jane Sterling - Algebra I All-in-One For Dummies
Здесь есть возможность читать онлайн «Mary Jane Sterling - Algebra I All-in-One For Dummies» — ознакомительный отрывок электронной книги совершенно бесплатно, а после прочтения отрывка купить полную версию. В некоторых случаях можно слушать аудио, скачать через торрент в формате fb2 и присутствует краткое содержание. Жанр: unrecognised, на английском языке. Описание произведения, (предисловие) а так же отзывы посетителей доступны на портале библиотеки ЛибКат.
- Название:Algebra I All-in-One For Dummies
- Автор:
- Жанр:
- Год:неизвестен
- ISBN:нет данных
- Рейтинг книги:5 / 5. Голосов: 1
-
Избранное:Добавить в избранное
- Отзывы:
-
Ваша оценка:
Algebra I All-in-One For Dummies: краткое содержание, описание и аннотация
Предлагаем к чтению аннотацию, описание, краткое содержание или предисловие (зависит от того, что написал сам автор книги «Algebra I All-in-One For Dummies»). Если вы не нашли необходимую информацию о книге — напишите в комментариях, мы постараемся отыскать её.
is the key! With it, you’ll get everything you need to solve the mystery of Algebra I.
This book proves that algebra is for everyone with straightforward, unit-based instruction, hundreds of examples and practice problems, and two quizzes for every chapter – one in the book and another (totally different!) online. From graph and word problems to the FOIL method and common algebra terminology,
walks you step-by-step through ALL the concepts you need to know to slay your Algebra I class.
In this handy guide, you’ll also:
Receive instruction and tips on how to handle basic and intermediate algebraic tasks such as factoring and equation simplification Banish math anxiety forever by developing an intuitive understanding of how algebra works Get a handle on graphing problems and functions, as well as inequalities and word problems
is a must-read for Algebra students looking for an everything-in-one-book supplement to their coursework, as well as anyone hoping to brush up on their math before tackling a related subject, such as physics, chemistry, or a more advanced math topic.
Q.Which is larger: 5.7 rounded to the nearest integer or [5.7]?
or
. Using the greatest integer function,
. So, rounding gives you the larger value.
rounded to the nearest integer and
.
to the nearest integer, you drop off the
, because its decimal value is about 0.333, or less than half; so,
rounds to 13. Applying the greatest integer function,
. So the values are the same.
Round 146.95 to the nearest integer.
Your last step will be to divide the result in the numerator by the result in the denominator. In the numerator, first do the subtraction in the parentheses, multiply that result by 3, and then subtract that product from 19. Finally, find the square root of the difference. In the denominator, do the subtraction in the parentheses, multiply the result by 4, subtract that product from 8, and then multiply the difference by 6. Finally, subtract 1 from the product. Then you can do the division indicated by the fraction line.
.Multiply each term in the parentheses by 4.
.Multiply each term in the parentheses by –3.
.This problem involves operations with fractions. You will see more on fractions in Chapter 4.
.
.