Dept = "IT", //---from IManager---
Street = "Kingston Street", //---from IAddress---
Zip = 12345 //---from IAddress---
};
Console.WriteLine(m1.Age()); //---from IPerson---
Console.WriteLine(m1.State()); //---from IAddress---
In addition to accessing the members of the Manager
class through its instance (in this case m1
), you can access the members through the interface that it implements. For example, since m1
is a Manager
object that implements both the IPerson
and IAddress
interfaces, you can cast m1
to the IPerson
interface and then assign it to a variable of type IPerson
, like this:
//---cast to IPerson---
IPerson p = (IPerson) m1;
This is known as interface casting. Interface casting allows you to cast an object to one of its implemented interfaces and then access its members through that interface.
You can now access members (the Age()
method and Name
and DateofBirth
properties) through p
:
Console.WriteLine(p.Age());
Console.WriteLine(p.Name);
Console.WriteLine(p.DateofBirth);
Likewise, you can cast the m1
to the IAddress
interface and then assign it to a variable to of type IAddress
:
//---cast to IAddress---
IAddress a = (IAddress) m1;
Console.WriteLine(a.Street);
Console.WriteLine(a.Zip);
Console.WriteLine(a.State());
Note that instead of creating an instance of a class and then type casting it to an interface, like this:
Manager m2 = new Manager();
IPerson p = (IPerson) m2;
You can combine them into one statement:
IPerson p = (IPerson) new Manager();
Performing a direct cast is safe only if you are absolutely sure that the object you are casting implements the particular interface you are trying to assign to. Consider the following case where you have an instance of the Employee
class:
Employee e1 = new Employee();
The Employee
class implements the IPerson
and IAddress
interfaces. And so if you try to cast it to an instance of the IManager
interface, you will get a runtime error:
//---Error: Invalid cast exception---
IManager m = (IManager) e1;
To ensure that the casting is done safely, use the is
operator. The is
operator checks whether an object is compatible with a given type. It enables you to rewrite the casting as:
if (m1 is IPerson) {
IPerson p = (IPerson) m1;
Console.WriteLine(p.Age());
Console.WriteLine(p.Name);
Console.WriteLine(p.DateofBirth);
}
if (m1 is IAddress) {
IAddress a = (IAddress) m1;
Console.WriteLine(a.Street);
Console.WriteLine(a.Zip); Console.WriteLine(a.State());
}
if (e1 is IManager) {
IManager m = (IManager) e1;
}
Using the is
operator means that the compiler checks the type twice — once in the is
statement and again when performing the actual casting. So this is actually not very efficient. A better way would be to use the as
operator.
The as
operator performs conversions between compatible types. Here's the preceding casting rewritten using the as
operator:
IPerson p = m1 as IPerson;
if (p != null) {
Console.WriteLine(p.Age());
Console.WriteLine(p.Name);
Console.WriteLine(p.DateofBirth);
}
IAddress a = m1 as IAddress;
if (a != null) {
Console.WriteLine(a.Street);
Console.WriteLine(a.Zip);
Console.WriteLine(a.State());
}
Employee e1 = new Employee();
//---m is null after this statement---
IManager m = e1 as IManager;
if (m != null) {
//...
}
If the conversion fails, the as operator returns null
, so you need to check for null
before you actually use the instance of the interface.
Overriding Interface Implementations
When implementing an interface, you can mark any of the methods from the interface as virtual
. For example, you can make the Age()
method of the Employee
class virtualso that any other classes that inherit from the Employee
class can override its implementation:
public interface IPerson {
string Name { get; set; }
DateTime DateofBirth { get; set; }
ushort Age();
}
public class Employee : IPerson {
public string Name { get; set; }
public DateTime DateofBirth { get; set; }
public virtual ushort Age() {
return (ushort)(DateTime.Now.Year - this.DateofBirth.Year);
}
}
Suppose there is a new class called Director
that inherits from the Employee
class. The Director
class can override the Age()
method, like this:
public class Director : Employee {
public override ushort Age() {
return base.Age() + 1;
}
}
Notice that the Age()
method increments the age returned by the base class by 1. To use the Director
class, create an instance of it and set its date of birth as follows:
Director d = new Director();
d.DateofBirth = new DateTime(1970, 7, 28);
When you print out the age using the Age()
method, you get 39 (2008–1970=38; increment it by 1 and the result is 39):
Console.WriteLine(d.Age()); //---39---
This proves that the overriden method in the Age()
method is invoked. If you typecast d to the IPerson
interface, assign it to an instance of the IPerson
interface, and invoke the Age()
method, it will still print out 39:
IPerson p = d as IPerson;
Console.WriteLine(p.Age()); //---39---
An interesting thing happens if, instead of overriding the Age()
method in the Director
class, you create a new Age()
class using the new
keyword:
public class Director : Employee {
public new ushort Age() {
return (ushort)(base.Age() + 1);
}
}
Create an instance of the Director
class and invoke its Age()
method; it returns 39, as the following statements show:
Director d = new Director();
d.DateofBirth = new DateTime(1970, 7, 28);
Console.WriteLine(d.Age()); //---39---
However, if you typecast d to an instance of the IPerson
interface and then use that interface to invoke the Age()
method, you get 38 instead:
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